2x^2)-5=(3x^2)-12x+31

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Solution for 2x^2)-5=(3x^2)-12x+31 equation: 



2x^2)-5=(3x^2)-12x+31

We move all terms to the left:

2x^2)-5-((3x^2)-12x+31)=0

We add all the numbers together, and all the variables

2x^2)-5-(3x^2-12x=0

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